TECHANGES Puzzle - January 2010

Fun with Numbers

How many ways can you make an expression that equals 2010 using each number from 1 to 9 and in cronological order? You can use any of the four operations (+, -, *, / ), you may use parentheses, and you must use each number only once. For example,

2010 = 1 + 2 - ( 3 - 4 - 5 ) * 6 * 7 * 8 - 9

How many can you come up with?

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Solutions:

2010 = 1 - ( 2 + ( 3 - 4 - 5 ) * 6 * 7 ) * 8 + 9
2010 = 1 + 2 + ( 3 + 4 * ( 5 + 6 * 7 + 8 ) ) * 9
2010 = 1 + 2 * ( 3 * 4 * ( 5 + 6 ) - 7 ) * 8 + 9
2010 = 1 * 2 * 3 * ( 4 * ( 5 * 6 + 7 * 8 ) - 9 )
2010 = 1 + 2 + ( 3 + 4 * ( 5 - 6 + 7 * 8 ) ) * 9
2010 = ( 1 - 2 - 3 + 4 * ( 5 / 6 + 7 * 8 ) ) * 9
2010 = ( 1 + 2 + 3 * 4 ) * ( 5 - 6 + ( 7 + 8 ) * 9 )
2010 = 1 + 2 + ( ( 3 * ( 4 + 5 ) + 6 ) * 7 - 8 ) * 9
2010 = ( 1 + 2 + 3 ) * ( 4 * ( 5 * 6 + 7 * 8 ) - 9 )
2010 = 1 + 2 + 3 * ( 4 * ( 5 + 6 ) * ( 7 + 8 ) + 9 )
2010 = ( 1 * 2 / 3 ) * ( ( 4 + 5 ) * 6 * 7 * 8 - 9 )
2010 = ( 1 - 2 - 3 ) * ( ( 4 + 5 ) / 6 - 7 * 8 * 9 )
2010 = ( 1 * 2 + ( 3 - 4 * ( 5 / 6 - 7 ) ) * 8 ) * 9
2010 = 1 * ( 2 + ( 3 - 4 * ( 5 / 6 - 7 ) ) * 8 ) * 9
2010 = ( 1 + 2 * ( 3 + 4 ) ) * ( 5 - 6 + ( 7 + 8 ) * 9 )

Click here to see additional solutions that allow for multi-digit numbers and decimals!